Continuity
A function is continuous if…
1. The limit exists at x=a
2. f(a) exists. In other words, if there is no hole/asymptote
3. The limit at x=a is equivalent to f(a)
Example where function is not continuous:
x+3, x
f(x)= 7, x=2
x^2+3x +1, x>4
This function is not continuous because limit as x approaches 4 from the left does not equal the limit as x approaches 4 from the right.
Intermediate Value Theorem
Working example:
F(x)=2x^2-16 on interval [1,3]
F(1)=2(1)^2-16 →2-16 → f(x)=-14
F(3)= 2(3)^2-16 = 18-16 = 2
Since f is continuous on [1,3] and f(1)< 0 < f(3), then there exists c in [1,3] such that f(c) = 0
failing example:
f(x)=x2+ x -9 on interval [1,2]
f(1)=(1)2 + 1 -9 = -7
f(2) = (2)^2 + 2 -9 = -3
Since f is continuous on [1,2] and f(1)< 0 >f(4), then it cannot be concluded that there exists c in [1,2] such that f(c) = 0
Derivatives
- Type 1: The derivative that is found using the limit as h approaches 0 of the difference quotient. f(x+h) - f(x)/h.
- f(x) = 3x + 2
- 3(x+h) +2 - (3x + 2)/h
- 3x+3h + 2 - 3x - 2/h
- 3h/h
- 3
- Type 2: The derivative that is found using the limit as x approaches a of the slope formula. f(x) - f(a)/ x-a
- f(x)= 4x- as x approaches 1
- 4x-4 - (4(1) -4)/x-1
- (4)(x-1)/x-1
- 4
A.) A derivative is a function that finds the slope of a curve of a polynomial.
B.) for me, the hardest part of finding a derivative is remembering to distribute the negative.
Instantaneous Velocity vs. Average Velocity
On your continuous example, there is no left side. So you are correct in that it does not match, but you should think about why it does not match instead of just stating that. Give me the values that actually make it not continuous. Next time try not to copy and paste that last definition, but give me your words or how you would find it. Someone else's definition or reasoning means less to you than your own.
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